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-5^3-5b=5b^2-180
We move all terms to the left:
-5^3-5b-(5b^2-180)=0
We add all the numbers together, and all the variables
-5b-(5b^2-180)-125=0
We get rid of parentheses
-5b^2-5b+180-125=0
We add all the numbers together, and all the variables
-5b^2-5b+55=0
a = -5; b = -5; c = +55;
Δ = b2-4ac
Δ = -52-4·(-5)·55
Δ = 1125
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1125}=\sqrt{225*5}=\sqrt{225}*\sqrt{5}=15\sqrt{5}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-15\sqrt{5}}{2*-5}=\frac{5-15\sqrt{5}}{-10} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+15\sqrt{5}}{2*-5}=\frac{5+15\sqrt{5}}{-10} $
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